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In this example, you will learn to store the information entered by the user using dynamic memory allocation.

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To understand this example, you should have the knowledge of the following C programming topics:

• C Pointers
• C Dynamic Memory Allocation
• C struct

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This program asks the user to store the value of noOfRecords and allocates the memory for the noOfRecords structure variables dynamically using the malloc() function.

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Demonstrate the Dynamic Memory Allocation for Structure

#include 
#include 
struct course {
    int marks;
    char subject[30];
};

int main() {
    struct course *ptr;
    int i, noOfRecords;
    printf("Enter the number of records: ");
    scanf("%d", &noOfRecords);

    // Memory allocation for noOfRecords structures
    ptr = (struct course *)malloc(noOfRecords * sizeof(struct course));
    for (i = 0; i < noOfRecords; ++i) {
        printf("Enter the name of the subject and marks respectively:\n");
        scanf("%s %d", (ptr + i)->subject, &(ptr + i)->marks);
    }

    printf("Displaying Information:\n");
    for (i = 0; i < noOfRecords; ++i)
        printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks);

    return 0;
}

Output

Enter the number of records: 2
Enter the name of the subject and marks respectively:
Programming
22
Enter the name of the subject and marks respectively:
Structure
33

Displaying Information:
Programming      22
Structure        33